Question

if a sine wave has a rms voltage of 12 volts what will be its peak-to-peak voltage

Answer 1

Since we know that $V_{rms}=\frac{1}{\sqrt{2}}V_{max}$ and $V_{peak\,to\,peak}=2V_{max}$ , we find the amplitud values for the peak-to-peak voltage as:

$V_{peak\,to\,peak}=(2\sqrt{2})V_{rms}=2\sqrt{2}(12\,V)=33.94\,V$

In conclusion, the peak-to-peak voltage of the sine wave is 33.94 V.

Reference:

• Young, H. D., & Freedman, R. A. (2015). University Physics with Modern Physics and Mastering Physics (p. 1632). Academic Imports Sweden AB.