A 36 ohm resistor and an 18 ohm resistor are connected in series across a 15V battery. What is the voltage across a) the 36 ohm resistor. b) the 18 ohm resistor?
Gives
R1=36Ω,R2=18ΩR_1=36\Omega,R_2=18\OmegaR1=36Ω,R2=18Ω
V=15V
Both resistance are series combination
Rnet=R1+R2R_{net}=R_1+R_2Rnet=R1+R2
Rnet=36+18=54ΩR_{net}=36+18=54\OmegaRnet=36+18=54Ω
Inet=VR=1554I_{net}=\frac{V}{R}=\frac{ 15}{54}Inet=RV=5415
Inet=0.277AI_{net}=0.277AInet=0.277A
V1=IR1=0.277×36=9.972VV_1=IR_1=0.277\times36=9.972VV1=IR1=0.277×36=9.972V
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