The sine wave represents Voltage Eab across the terminal a, b of an AC motor that operates at 50 Hz. Knowing that 0=30 and Em = 100V, find the voltage at t=0 and t= 27.144 S.
As per the given question,
The voltage at t= 0 is,
Eab=Emcos(360ft+θ)E_{ab}=E_m \cos(360ft+\theta)Eab=Emcos(360ft+θ)
Now, substituting the values,
=100cos(360×50×0+30∘)=100\cos(360\times 50\times0+30^\circ)=100cos(360×50×0+30∘) V
=100cos(30∘)=100\cos(30^\circ)=100cos(30∘) V
=86.6V=86.6V=86.6V
The voltage at t= 27.144
⇒Eab=100cos(360×50×27.144+30∘)\Rightarrow E_{ab}=100\cos(360\times 50\times 27.144+30^\circ)⇒Eab=100cos(360×50×27.144+30∘)
⇒Eab=100cos(488622∘)\Rightarrow E_{ab}=100\cos(488622^\circ)⇒Eab=100cos(488622∘)
⇒Eab=−20.8V\Rightarrow E_{ab}=-20.8V⇒Eab=−20.8V
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment