A certain oscillator satisfies the equation of motion: 𝑥••+ 4x = 0. Initially the particle is at
the point x = √3 when it is projected towards the origin with speed 2.
2.1. Show that the position, x, of the particle at any given time, t, is given by:
x = √3 cos 2t – sin 2t.
"\\ddot x+4x=0,"
"x=c_1\\cos 2t+c_2\\sin 2t,"
"\\dot x=2c_2\\cos 2t-2c_1\\sin 2t,"
"c_1=\\sqrt 3,"
"c_2=1,"
"x=\\sqrt 3\\cos 2t+\\sin 2t ."
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