Answer to Question #299244 in Classical Mechanics for Mafydre

Question #299244

A body of 4kg mass travelling at 8m/s² collides with a stationary body of mass 12kg, both being constrainted in their motion by the same frictionless guides. Find their velocities and loss of kinetic energy, if coefficient of restitution is 1 and (b) if it is 0.5

1
Expert's answer
2022-02-18T08:22:14-0500

Given:

"v_1=8\\:\\rm m\/s"

"m_1=4.0\\:\\rm kg"

"v_2=0"

"m_2=12\\:\\rm kg"


(a) "e=1"

"|v_1'-v_2'|=|v_1-v_2|=8"

Hence


"m_1v_1=m_1v_1'+m_2(8-v_1')"

"4*8=4v_1'+12(8-v_1')"

"v_1'=8\\:\\rm m\/s"

"v_2'=0"

The loss of kinetic energy is zero.

(b) "e=0.5"

"|v_1'-v_2'|=0.5|v_1-v_2|=4"

Hence


"m_1v_1=m_1v_1'+m_2(v_1'-0.5v_1)"

"4*8=4v_1'+12(v_1'-4)"

"v_1'=5\\:\\rm m\/s"

"v_2'=1\\:\\rm m\/s"

The loss of kinetic energy

"\\Delta E=4*8^2\/2-(4*5^2\/2+12*1^2\/2)"

"\\Delta E=72\\:\\rm J"


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