Question

According to Yukawa theory of Nuclear forces, the attractive force between two Nucleons has the potential V(r)=Ke^-ar/r What will be the Nuclear force?

Answer 1

$U(r)=\frac{Ke^{-ar}}r,$

$F=U'=\frac{-arKe^{-ar}-Ke^{-ar}}{r^2}=\frac{-Ke^{-ar}(1+ar)}{r^2}.$