Answer to Question #290642 in Classical Mechanics for Shah

Question #290642

According to Yukawa theory of Nuclear forces, the attractive force between two Nucleons has the potential V(r)=Ke^-ar/r What will be the Nuclear force?

Expert's answer

"U(r)=\\frac{Ke^{-ar}}r,"

"F=U'=\\frac{-arKe^{-ar}-Ke^{-ar}}{r^2}=\\frac{-Ke^{-ar}(1+ar)}{r^2}."

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