Question

the 600N force applied to the bracket at A is to be replaced by two forces , Fa in the a-a direction and Fb in the b-b direction, which together produce the same effect on the bracket as that of 600- N force determine Fa and Fb

Answer 1

$F_a=\frac F{\cos 30°}=\frac{2\cdot 600}{\sqrt3}=692.82~N.$

$F_b=\frac F{2\sin60°}=\frac{600}{\sqrt3}=346.41~N.$