the 600N force applied to the bracket at A is to be replaced by two forces , Fa in the a-a direction and Fb in the b-b direction, which together produce the same effect on the bracket as that of 600- N force determine Fa and Fb
"F_a=\\frac F{\\cos 30\u00b0}=\\frac{2\\cdot 600}{\\sqrt3}=692.82~N."
"F_b=\\frac F{2\\sin60\u00b0}=\\frac{600}{\\sqrt3}=346.41~N."
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