Question

An energy source forces a constant current of 2 A for 10 s to flow
through a light bulb. If 2.3 kJ is given off in the form of light and heat
energy, calculate the voltage drop across the bulb.

Answer 1

Total charge;

$\Delta q=i\Delta t=2\times10=20C$

Voltage Drop;

$v=\frac{\Delta w}{\Delta q}=\frac{2.3\times10^3}{20}=115V$