Question #80978
What is keplers 3rd law
Expert's answer
The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
mrω^2=G mM/r^2 → mr(2π/T)^2=G mM/r^2 → T^2=((4π^2)/GM) r^3 → T^2∝r^3
mrω^2=G mM/r^2 → mr(2π/T)^2=G mM/r^2 → T^2=((4π^2)/GM) r^3 → T^2∝r^3
Learn more about our help with Assignments: Astronomy
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
#339914 on Dec 2023
#339914 on Dec 2023
Comments