If cos(𝜃 ) = 1/3 and tan( 𝜃 ) < 0 , find the exact value of each of the remaining trigonometric functions of 𝜃
if cos θ\thetaθ >0 and tan θ\thetaθ <0 then this falls on the fourth quadrant. The sin will also be negative.
let x be the adjacent, y the opposite and r the hypotenuse of a right angled triangle where θ\thetaθ is the angle formed as x and r intersect.
cosθ=xrcos \theta=\frac x rcosθ=rx
x=1, r=3
y=r2−x2y=\sqrt {r^2-x^2}y=r2−x2
y=32−12=8y=\sqrt{3^2-1^2}=\sqrt 8y=32−12=8
secθ=1cosθ=113=3sec \theta=\frac{1}{cos \theta}=\frac{1}{\frac 1 3}=3secθ=cosθ1=311=3
sinθ=−yr=−83\sin \theta =-\frac y r=- \frac {\sqrt{8}}3sinθ=−ry=−38
cscθ=1sinθ=1−83=−38\csc \theta =\frac 1 {sin\theta}=\frac {1}{-\frac {\sqrt 8}{3}}=-\frac{3}{\sqrt 8}cscθ=sinθ1=−381=−83
tanθ=−yx=−81=−8\tan \theta =-\frac y x=-\frac {\sqrt 8} 1=-\sqrt 8tanθ=−xy=−18=−8
cotθ=1tanθ=−18\cot \theta=\frac{1}{tan \theta}=-\frac{1}{\sqrt 8}cotθ=tanθ1=−81
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