Question

Given the standardized normal distribution (with a mean of 0 and a standard deviation of 1, as in Table E.2). What is the probability that Z is greater than 1.08?

Answer 1

From z-score table we have that $P(z<1.08)=0.8599.$

$P(z>1.08)=1- 0.8599=0.1401=14.01\%.$

Answer: 14.01%