Question

A box contains 6 red balls, 4 white balls and 5 blue balls. Determine the probability of chasing two red balls and 1 white ball if the balls are not replaced after being drawn using combination method

Answer 1

$$P(2R\&\ 1W)=\dfrac{\dbinom{6}{2}\dbinom{4}{1}\dbinom{5}{0}}{\dbinom{6+4+5}{2+1}}$$

$$=\dfrac{15(4)(1)}{455}=\dfrac{12}{91}$$