Check whether the function f given by
f(x)=1/(2x-4)^2 ∀x∈]-2,2[
Is continuous in the interaval ]-2,2] but not bounded in the interval (-2,2)
The function is continuous since it is rational function with the denominator non-zero on (-2,2). It is not bounded since "f(2-\\frac{1}{2n})=n^2\\to +\\infty, n\\to\\infty"
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