Question #308415

Give an example of a divergent sequence which has two convergent subsequences.


Justify your claim.

Expert's answer

Sequence an=sin⁡(πn/2)a_n = \sin(\pi n/2) is divergent, since it oscillates between −1,0,1-1, 0, 1 as n→∞n\to\infty. However, if we take only even n=2kn=2k, subsequence a2k=sin⁡(πk)a_{2k} = \sin(\pi k) will converge to as k→∞k\to \infty.

We can also take n=4k+1n = 4k+1 and the subsequence a4k+1=sin⁡(2πk+π/2)a_{4k+1} = \sin(2\pi k+\pi/2) will converge to 11 as k→∞k\to \infty.


Answer. an=sin⁡(πn/2)a_n = \sin(\pi n/2).


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