Question #299118

Find


lim tan x sec^2 x- x/x^3


x→0

Expert's answer

lim⁡x→0tan⁡xsec⁡2x−xx3=lim⁡x→0(tan⁡xsec⁡2x−x)′(x3)′\lim\limits_{x\to0}\dfrac{\tan x\sec^2 x-x}{x^3}=\lim\limits_{x\to0}\dfrac{(\tan x\sec^2 x-x)'}{(x^3)'}

=lim⁡x→0sec⁡4x+2tan⁡2xsec⁡2x−13x2=\lim\limits_{x\to0}\dfrac{\sec^4 x+2\tan^2 x\sec^2 x-1}{3x^2}

=lim⁡x→0sec⁡2x(1+tan⁡2x)+2tan⁡2xsec⁡2x−13x2=\lim\limits_{x\to0}\dfrac{\sec^2 x(1+\tan ^2 x)+2\tan^2 x\sec^2 x-1}{3x^2}

=lim⁡x→0tan⁡2x+3tan⁡2xsec⁡2x3x2=\lim\limits_{x\to0}\dfrac{\tan ^2 x+3\tan^2 x\sec^2 x}{3x^2}

=13lim⁡x→0tan⁡2xx2+33lim⁡x→0tan⁡2xx2(lim⁡x→0sec⁡2x)=\dfrac{1}{3}\lim\limits_{x\to0}\dfrac{\tan ^2 x}{x^2}+\dfrac{3}{3}\lim\limits_{x\to0}\dfrac{\tan ^2 x}{x^2}(\lim\limits_{x\to0}\sec^2 x)

=13(1)+1(1)=43=\dfrac{1}{3}(1)+1(1)=\dfrac{4}{3}


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