Question #217040

For x and y in R, let d(x,y)=(|x-y|)/(1+|x-y|),prove that d defines a.bounded metric on R


Expert's answer

1)

Positivity: d(x,y)≥0d(x,y)\ge0 with equality if x=y


2)

Symmetry: d(x,y)=d(y,x)d(x,y)=d(y,x)

∣x−y∣1+∣x−y∣=∣y−x∣1+∣y−x∣\frac{|x-y|}{1+|x-y|}=\frac{|y-x|}{1+|y-x|}


3)

Triangle Inequality: d(x,y)≤d(x,z)+d(z,y)d(x,y)\le d(x,z)+d(z,y)

d(x,y)=∣x−y∣1+∣x−y∣=∣(x−z)+(z−y)∣1+∣(x−z)+(z−y)∣≤∣(x−z)+(z−y)∣1+∣(x−z)+(z−y)∣=d(x,z)+d(z,y)d(x,y)=\frac{|x-y|}{1+|x-y|}=\frac{|(x-z)+(z-y)|}{1+|(x-z)+(z-y)|}\le \frac{|(x-z)+(z-y)|}{1+|(x-z)+(z-y)|}=d(x,z)+d(z,y)


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