Answer to Question #170338 in Real Analysis for Prathibha Rose

Question #170338

Show by an example that in general a continuous function is neither convex nor concave


1
Expert's answer
2021-03-31T13:54:38-0400

Take the sine function. Then take any two points a,b from [0,π].[0,\pi]. Then in this range the function is convex. The reason is f(x)=sin xf(x)=sin x<0.f(x)=sin \ x\Rightarrow f^{''}(x)=-sin \ x <0. Since in the given range the sine function is positive. Again from [π,2π],f(x)>0[\pi,2\pi ], f^{''}(x)>0 since in the given range the sin function is negative.Hence in that range the function is concave. Hence in general a continuous function is neither concave or convex.


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