Answer to Question #45972 in Integral Calculus for victor

Question

Find
∫e2xdx

Answer 1

∫e^(2x)dx=(1/2)*∫e^(2x)d(2x)=|substitution t=2x|=(1/2)*∫e^tdt=(1/2)*e^t+C=(1/2)*e^2x+C, where C is an arbitrary real constant.