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Answer to Question #45968 in Integral Calculus for victor
Question #45968
Find the integral with respect to
x:∫cosxsinxdx
x:∫cosxsinxdx
Expert's answer
∫cosxsinxdx=(1/2)*∫sin(2x)dx=-(1/2)*cos(2x)/2+C=-(1/4)cos(2x)+C, where C is an arbitrary real constant.
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