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Answer to Question #45956 in Integral Calculus for victor

Question #45956
Integrate completely with respect to x :
∫10(7−4x)2dx
1
Expert's answer
2014-09-11T12:59:30-0400
∫10(7−4x)2dx=10∫(7−4x)2dx=10∫(49-56x+16x2)dx=10(∫49dx-56∫xdx+16∫x2dx)=10(49∫dx-56∫xdx+16∫x2dx)=10(49x-56x2/2+16x3/3)+C=490x-280x2+160x3/3+C, where C is an arbitrary real constant.

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