Answer to Question #45955 in Integral Calculus for victor

Question #45955

Integrate with respect to x :
∫10(2x2−4x−6)

Expert's answer

∫10(2x²−4x−6)dx=10∫(2x²−4x−6)dx=10∫2x²dx-10∫4xdx-10∫6dx=20∫x²dx-40∫xdx-60∫dx=20x³/3-40x²/2-60x+C, where C is an arbitrary real constant.

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