Answer to Question #41147 in Integral Calculus for DEEPU SINGH

Question

The surface f(x,y)=x2+y2 has a minimum at (0,0) .

Answer 1

It is true, because x^2+y^2 is non-negative expression. So, the minimum of function f(x,y)=x^2+y^2 equals 0, when x=0 and y=0.