Let us list the members of these sets.
(a) A = { x ∣ x is a real number such that x 2 = 5 } A=\{x | x\text{ is a real number such that }x^2 = 5\} A = { x ∣ x is a real number such that x 2 = 5 }
It follows that A = { − 5 , 5 } . A=\{-\sqrt{5},\sqrt{5}\}. A = { − 5 , 5 } .
(b) B = { x ∣ x is a positive integer less than 15 } B=\{x | x\text{ is a positive integer less than 15}\} B = { x ∣ x is a positive integer less than 15 }
It follows that B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13 , 14 } . B=\{1,2,3,4,5,6,7,8,9,10,11,12,13,14\}. B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13 , 14 } .
(c) C = { x ∣ x is the square of an integer and x < 200 } C=\{x | x\text{ is the square of an integer and }x < 200\} C = { x ∣ x is the square of an integer and x < 200 }
It follows that C = { 0 , 1 , 4 , 9 , 16 , 25 , 36 , 49 , 64 , 81 , 100 , 121 , 144 , 169 , 196 } . C=\{0,1,4,9,16,25,36,49,64,81,100,121,144,169,196\}. C = { 0 , 1 , 4 , 9 , 16 , 25 , 36 , 49 , 64 , 81 , 100 , 121 , 144 , 169 , 196 } .
(d) D = { x ∣ x is an integer such that x 2 = 5 } D=\{x | x\text{ is an integer such that }x^2 = 5\} D = { x ∣ x is an integer such that x 2 = 5 }
Since the equation x 2 = 5 x^2=5 x 2 = 5 has no integer roots, D = ∅ . D=\emptyset. D = ∅.
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