Question #252334

Define a partial differential equation and give an example.

Hence find the differential equation arising from F[y/x,z/x3]=0


1
Expert's answer
2021-11-03T18:18:17-0400

The partial differential equation is an equation which imposes relations between the various partial derivatives of a multivariable function. For exaple, d2udx2d2udy2=0.\frac{d^2u}{d x^2}-\frac{d^2u}{d y^2}=0.

Let's find the differential equation arising from F[y/x,z/x3]=0F[y/x,z/x3]=0 .

Let f(x;y;z)=F(yx;zx3).f(x;y;z)=F\left(\frac{y}{x};\frac{z}{x^3}\right).

f(x)=yx2Fx13zx4Fx1;f(y)=Fx1/x;f(z)=Fx1/x3.f'(x)=-\frac{y}{x^2}F'_{x_1}-3\frac{z}{x^4}F'_{x_1}; f'(y)=F'_{x_1}/x; f'(z)=F'_{x_1}/x^3. So we have Fx1=xf(x);Fx2=x3f(z)F'_{x_1}=xf'(x); F'_{x_2}=x^3f'(z) . Since the function x(y;z)x(y;z) can be given by from the equality f(x;y;z)=0f(x;y;z)=0 by the implicit function theorem. We have x(y)=f(y)f(x),x(z)=f(z)f(x).x'(y)=-\frac{f'(y)}{f'(x)}, x'(z)=-\frac{f'(z)}{f'(x)}. From the equality f(x)=yx2Fx13zx4Fx1f'(x)=-\frac{y}{x^2}F'_{x_1}-3\frac{z}{x^4}F'_{x_1} we have 1=yxx(y)+3zxx(z)1=\frac{y}{x}x'(y)+3\frac{z}{x}x'(z) or yx(y)+3zx(z)=x.yx'(y)+3zx'(z)=x.


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