Obtain the general solution of the following equations.
1. (4π₯π¦ + 3π¦2 )ππ₯ + π₯(π₯ + 2π¦)ππ¦ = 0
2. (3π₯3 + π¦2 )ππ₯ β 2π₯π¦ππ¦ = 0
Obtain the particular solution satisfying the indicated conditions.
3. (4π₯3 β 3π¦2 )ππ₯ + 6π₯π¦ππ¦ = 0, π¦(β1) = 0
Comments
Leave a comment