solve the initial value problem y''-4y'-5y=0 for y(0)=0 and y'(0)=6
Auxiliary equation,
m2-4m-5=0
solving the equation, we get
m=-1, 5
Therefore, general solution is
"y=c_1e^{-x}+c_2e^{5x}"
Then,
"y'=-c_1e^{-x}+5c_2e^{5x}"
By using initial conditions,
"y(0)=c_1+c_2=0\\\\\nand\\\\\ny'(0)=-c_1+5c_2=6"
solving above two equations, we get
"c_1=-1 ,c_2=1"
Therefore, solution of the given initial value problem is y=-e-x +e5x.
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