verify that each given function is a solution of the
differential equation.
5.y′′\:−\:y\:=\:0;\:y\left(t\right)\:=\:e^t
Let us verify that the function "y(t)=e^t" is a solution of the differential equation "y''-y=0". Since "y'(t)=e^t" and "y''(t)=e^t," we conclude that "y''(t)-y(t)=e^t-e^t=0," and hence "y(t)=e^t" is a solution of the differential equation "y''-y=0".
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