Answer to Question #229855 in Differential Equations for Adi

Question #229855
(1+x)
1
Expert's answer
2021-09-01T09:58:01-0400

The question seems to be incomplete, so we assuming it as:

"\\frac{dy}{dx}=1+x\\\\\n\\Rightarrow dy=(1+x)dx\\\\"

Integrating both sides, we get:

"y=x+\\frac{x^2}{2}+c" where "c" is the constant of integration.


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