Answer to Question #213964 in Differential Equations for rer

Question

3.A single individual starts a rumour in a community of 200 people. the rumour spread at a rate proportional to the number of people who have not yet heard the rumour. After 2days 10 people have heard the rumour

1. how many people will have heard the rumour after 5days
2. how long will it take for the rumour to spread to 100 people

Answer 1

If $N$ denotes the number of people who have heard the rumor, then $200-N$ represents the number of people who haven’t heard the rumor.

Then

$$\dfrac{dN}{dt}=k(200-N)$$

$$\dfrac{dN}{200-N}=kdt$$

Integrate

$$\ln|200-N|=-kt+\ln C$$

$$N=200-Ce^{-kt}$$

$$N(0)=200-C=0=>C=200$$

$$N=200-200e^{-kt}$$

$$N(2)=200-200e^{-k(2)}=10$$

$$e^{-k(2)}=0.95$$

$$2k=-\ln0.95$$

$$k=-\dfrac{1}{2}\ln0.95$$

$$N(t)=200-200e^{(\ln0.95)t/2}$$

$$N(t)=200-200(0.95)^{t/2}$$

1.

$$N(5)=200-200(0.95)^{5/2}=24$$

2.

$$N(t)=200-200e^{(\ln0.95)t/2}=100$$

$$e^{(\ln0.95)t/2}=0.5$$

$$(\ln0.95)t=2\ln0.5$$

$$t=\dfrac{2\ln0.5}{\ln0.95}$$

$$t=27\ days$$