Question #16722

For any ring k, let A subspace of M(2,k) where a11+a21=a12+a22. Show that A is a subring of M2(k), and that it is isomorphic to the ring R of 2 × 2 lower triangular matrices over k.
1

Expert's answer

2012-10-18T08:08:18-0400

Let α=(1101)\alpha = \begin{pmatrix} 1 & 1 \\ 0 & 1 \end{pmatrix} . Then α1Rα\alpha^{-1}R\alpha consists of the matrices


(1101)(x0yz)(1101)=(xyxyzyy+z)\left( \begin{array}{cc} 1 & -1 \\ 0 & 1 \end{array} \right) \left( \begin{array}{cc} x & 0 \\ y & z \end{array} \right) \left( \begin{array}{cc} 1 & 1 \\ 0 & 1 \end{array} \right) = \left( \begin{array}{cc} x - y & x - y - z \\ y & y + z \end{array} \right)


We see easily that the set of these matrices is exactly AA . Therefore, AA is just a "conjugate" of the subring RR in the ring M2(k)\mathbf{M}2(k) . In particular, ARA \sim R .

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