Question

An antacid tablet containing 1.25 g NaHCO3 is dissolved in water and the total volume of solution is
500.0 mL. Calculate the molarity of this NaHCO3 solution.

Answer 1

C_M = n / V

n = m / M

M (NaHCO₃) = 84.01 g/mol

n (NaHCO₃) = 1.25 / 84.01 = 0.015 mol

C_M (NaHCO₃) = 0.015 / 0.5000 = 0.03 M