Question

Q: Two fruitfies were crossed, one was heterozygous (Aa Bb) and another homozygous recessive. The result was flies with AB : ab = 1:1. It a case of .....

Ans: I think it should be complete linkage. Had it been independent assortment There woulsn't have been just two phenotypes/ combination but four and the ration would have been 1:1:1:1

Neither incomplete because there are not four phenotypes and they are neither in non 1:1:1:1 ratio. There was another option though epistasis(provided), this has to be ruled out. Am I right?